4x^2+2+56x=128

Solution for 4x^2+2+56x=128 equation:

4x^2+2+56x=128

We move all terms to the left:

4x^2+2+56x-(128)=0

We add all the numbers together, and all the variables

4x^2+56x-126=0

a = 4; b = 56; c = -126;
Δ = b2-4ac
Δ = 562-4·4·(-126)
Δ = 5152
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5152}=\sqrt{16*322}=\sqrt{16}*\sqrt{322}=4\sqrt{322}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-4\sqrt{322}}{2*4}=\frac{-56-4\sqrt{322}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+4\sqrt{322}}{2*4}=\frac{-56+4\sqrt{322}}{8}
$